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<> The 11th Blue Bridge Cup software provincial competition
<> test questions A: Running training
Total score of this question ：5 branch
【 Problem description 】
Xiao Ming is going to do a running training .
Initial time , Xiao Ming is full of energy , Physical strength is calculated as 10000. If Xiao Ming runs , Loss per minute
600 Physical strength . If Xiao Ming has a rest , Increase per minute 300 Physical strength . The loss and increase of physical strength are
Uniformly varying .
Xiao Ming is going to run for a minute , Take a minute off , Run for another minute , Take another minute off …… So follow
ring . If Xiao Ming's physical strength arrives at a certain time 0, He stopped exercising .
How long will Xiao Ming stop exercising . To make the answer an integer , Please output the answer in seconds .
Only fill in the number in the answer , Do not fill in company .
【 Answer submission 】
This is a result filling question , You just need to calculate the results and submit them . The result of this question is a
integer , Only fill in this integer when submitting the answer , If you fill in extra content, you will not be able to score .
Problem solution
You can count by mouth here ： The answer is ：3880
10000 / (600-300) == 33.33 33*(600-300) = 9900 10000 - 9900 + 300 = 400 < 600
So the time is 32*2*60 + 400/10 = 3880
Program simulation :
energy = 10000 min = 0 second = 0 while(energy): min += 1 if min % 2 == 1: if
energy> 600 : energy -= 600 else: min -= 1 second = energy/10 energy = 0 else:
energy+= 300 if energy <= 0: break print(min*60+second)
<> test questions B: anniversaries of important events
Total score of this question ：5 branch
【 Problem description 】
2020 year 7 month 1 Day is ***（ Sensitive word ） establish 99 Anniversary .
***（ Sensitive word ） Founded in 1921 year 7 month 23 day .
Excuse me from 1921 year 7 month 23 Sunday noon 12 When to 2020 year 7 month 1 Sunday noon 12 When the total package
How many minutes ?
【 Answer submission 】
This is a result filling question , You just need to calculate the results and submit them . The result of this question is a
integer , Only fill in this integer when submitting the answer , If you fill in extra content, you will not be able to score .
Problem solution
Let's go straight to the program , perhaps Excel Dafa is OK . Used here Python Convenient point , Fill in the blanks ,Python Code is ：
def fun(year): if (year%4==0 and year%100!=0) or year%400==0: return 366 return
365 day = 0 for i in range(1922,2021): day += fun(i) # 1921.7.23 reach 2020.7.23 Number of days
# Further reduction 22 day day = day - 22 min = day * 24 * 60 print(min)
answer ：52038720
<> test questions C: Merge detection
Total score of this question ：10 branch
【 Problem description 】
***（ Sensitive word ） from ***（ Sensitive word ） cause , Recently in A National spread , In order to control as soon as possible ***（ Sensitive word ）,A
China is ready to test a large number of people for virus nucleic acid . however , Kits for testing are in short supply . In order to solve this difficulty , Scientists have come up with an idea ： Merge detection . Coming from multiple people （k individual ） The collected samples are put into the same kit for testing . If the result is negative , This means that
k Everyone is negative , It's done with a kit k Personal testing . If the result is positive , At least one person is positive , This needs to be k All individual samples were retested independently （ In theory , If before testing
k 1 If individuals are negative, it can be inferred that k Individuals are positive , However, this inference will not be used in practice , But will k Individual independent testing ）, Plus the initial merge detection , A total of k + 1
A kit is complete k Personal testing .A China estimates that the infection rate of the people tested is about 1%, Evenly distributed . Excuse me? k How many kits can you save most ?
【 Answer submission 】
This is a result filling question , You just need to calculate the results and submit them . The result of this question is a
integer , Only fill in this integer when submitting the answer , If you fill in extra content, you will not be able to score .
Problem solution
This is a mathematical problem Set the total number as pop, infection rate p, every time k people , Total city series sum sum = ([pop/k]+1)*(1+k*p(k+1)) there [pop/k]+1)
Namely pop/k Round up [pop/k]+1) Here because pop Large quantity , So it's rounded up here 1 Can be ignored , Take it directly here pop/k, Namely sum = (pop/k)*(1+
kp(k+1)) take p Substitute in sum = (pop/k)*(1+k*0.01(k+1)) sum Derivation = (pop/k)(0.01k-1/k) Appropriate k = 10
Time ,sum Take the minimum value therefore K= 10
answer ：10
<> test questions D: REPEAT program
Total score of this question ：10 branch
【 Problem description 】
enclosure prog.txt Is a program written in a certain language .
among REPEAT k Indicates that a number of times is k Cycle of . The range of loop control is expressed by indentation ,
The number of consecutive indents from the next line that are greater than that line （ The space in front is longer ） Content included for the loop .
For example, the following fragment ：
REPEAT 2:
A = A + 4
REPEAT 5:
REPEAT 6:
A = A + 5
A = A + 7
A = A + 8
A = A + 9
From this clip A = A + 4 Line to A = A + 8 All lines are in the first line
In two cycles .
REPEAT 6: Line to A = A + 7 All the lines are in REPEAT 5: In circulation .
A = A + 5 The actual total number of cycles is 2 × 5 × 6 = 60 second .
After the execution of the program ,A What is the value of ?
【 Answer submission 】
This is a result filling question , You just need to calculate the results and submit them . The result of this question is a
integer , Only fill in this integer when submitting the answer , If you fill in extra content, you will not be able to score .
Problem solution
This question is to fill in the blanks , So we can still use Python To deal with it , It can be more convenient , current ,C/C++ It's OK , Here is an example Python Handling method of version
dir = '/Users/qiguan/Downloads/C++ university B group /REPEAT program .txt' file = open(dir) data =
file.read() len = data.__len__() def get_indent(i): now_indent = 0 while data[i]
== ' ': now_indent = now_indent + 1 i = i + 1 return now_indent, i def get_flag(
i): if data[i] == 'R': i = i + 7 return 1, i if data[i] == 'A': i = i + 8 return
2, i # The number of indented spaces before the line in the current process indent = 0 # Control subscript i = 5 # A Value of A = 0 # multiplier multiplier = 1 #
multiplier aggregate multiplier_list= [] flag = 0 while i != len: if data[i] == '\n': i = i + 1
if i >= len -1: break now_indent, i = get_indent(i) flag, i = get_flag(i) if
now_indent< indent: multiplier /= multiplier_list[-1] multiplier_list.pop() if
flag== 1: multiplier *= int(data[i]) multiplier_list.append(int(data[i])) i += 2
# A = A + if flag == 2: A += int(data[i])*multiplier i += 1 indent = now_indent
print(A)
answer ：241830
<> test questions E: matrix
Total score of this question ：15 branch
【 Problem description 】
hold 1 ∼ 2020 Put on 2 × 1010 In the matrix . The right side of the same line is required to be larger than the left , same
The lower column is larger than the upper one . How many options are there ?
The answer is big , You just need to give the number of schemes divided by 2020 The remainder of .
【 Answer submission 】
This is a result filling question , You just need to calculate the results and submit them . The result of this question is a
integer , Only fill in this integer when submitting the answer , If you fill in extra content, you will not be able to score .
Problem solution
#include <iostream> using namespace std; int main(){ int (*dp)[1011] = new int
[2021][1011]; dp[1][1] = 1; for (int i = 2; i <= 2020; ++i) { for (int j = 1; j
<= i; ++j) { dp[i][j] += dp[i-1][j-1]; if(i-j<=j){ dp[i][j] += dp[i-1][j]; } dp[
i][j] %= 2020; } } cout<<dp[2020][1010]; return 0; }
answer ：1340
<> test questions F: Divisible sequence
time limit : 1.0s Memory limit : 256.0MB Total score of this question ：15 branch
【 Problem description 】
There is a sequence , The first number in the sequence is n, Each subsequent number is divided by the previous number 2, Please enter
Find the items with positive values in this sequence .
【 Input format 】
The input line contains an integer n.
【 Output format 】
Output one line , Contains multiple integers , Adjacent integers are separated by a space , Indicates the answer .
【 sample input 】
20
【 sample output 】
20 10 5 2 1
【 Scale and agreement of evaluation cases 】
about 80% Evaluation cases for ,1 ≤ n ≤ 10^9.
For all profiling cases ,1 ≤ n≤ 10^18.
Problem solution
#include <iostream> using namespace std; int main(){ long long int n; cin>>n;
while(n){ // Large amount of output data , use printf Better // In the Blue Bridge Cup system ,lld Should be used %I64d printf("%lld ",n); n =
n>>1; } return 0; }
<> test questions G: decode
time limit : 1.0s Memory limit : 256.0MB Total score of this question ：20 branch
【 Problem description 】
Xiao Ming has a long string of English letters , May contain uppercase and lowercase .
In this string of letters , There are many consecutive ones that are repeated . Xiao Ming thought of a way to put the alphabet
Reach shorter ： Write consecutive identical letters into letters + Form of number of occurrences .
for example , successive 5 individual a, Namely aaaaa, Xiao Ming can be abbreviated as a5（ It may also be abbreviated to a4a,
aa3a etc. ）. For this example ：HHHellllloo, Xiao Ming can be abbreviated as H3el5o2. For the convenience of the watch
reach , Xiao Ming will not continuously exceed 9 Write the same characters in short form .
Now give the abbreviated string , Please help Xiao Ming restore the original string .
【 Input format 】
The input line contains a string .
【 Output format 】
Output a string , Represents the restored string .
【 sample input 】
H3el5o2
【 sample output 】
HHHellllloo
【 Scale and agreement of evaluation cases 】
For all profiling cases , The string consists of upper and lower case English letters and numbers , Length not exceeding
100.
Please note that the original string length may exceed 100.
Problem solution
#include <iostream> #include <string> #include <cstring> #include <cstdio>
using namespace std; int main(){ string a; getline(cin,a); int len = a.length();
string re= ""; bool flag = false; for(int i = 0 ; i < len;i++){ if(a[i] < '2'
|| a[i] > '9'){ re = re + a[i]; flag = true; } else{ // The previous one is not 2-9, And this time 2-9 number if(
flag){ int num = int(a[i] - '0') - 1; for (int j = 0; j < num; ++j) { re = re +
a[i-1]; } flag = false; } else{ re = re + a[i]; } } } cout<<re; return 0; }
<> test questions H: Walk grid
time limit : 1.0s Memory limit : 256.0MB Total score of this question ：20 branch
【 Problem description 】
There are some two-dimensional lattice on the plane .
These points are numbered like two-dimensional arrays , From top to bottom 1 To n that 's ok ,
From left to right 1 To m column , Each point can be represented by row number and column number .
Now there is a man standing on the second floor 1 Line number 1 column , To go to the third n Line number m column . Only right or down
go .
be careful , If the number of rows and columns are even , You can't go into this space .
How many options are there .
【 Input format 】
The input line contains two integers n, m.
【 Output format 】
Output an integer , Indicates the answer .
【 sample input 】
3 4
【 sample output 】
2
【 sample input 】
6 6
【 sample output 】
0
【 Scale and agreement of evaluation cases 】
For all profiling cases ,1 ≤ n ≤ 30, 1 ≤ m ≤ 30.
Problem solution
#include <iostream> #include <vector> using namespace std; int main(){ int n,m;
cin>>n>>m; vector<vector<int>> dp(n+1,vector<int>(m+1)); for(int i = 1;i <= n;i
++){ dp[i][1] = 1; } for (int j = 1; j <= m; ++j) { dp[1][j] = 1; } for(int i =
2;i <= n;i++){ for (int j = 2; j <= m; ++j) { if(i%2==0 && j%2==0) continue;
else dp[i][j] = dp[i-1][j] + dp[i][j-1]; } } cout<<dp[n][m]; return 0; }
<> test questions I: Integer splicing
time limit : 1.0s Memory limit : 256.0MB Total score of this question ：25 branch
【 Problem description 】
Define a length of n Array of A1, A2, · · · , An. You can choose two numbers from them Ai and Aj
(i Not equal to j), Then Ai and Aj Put one before another into a new integer . for example 12 and 345 can
To spell 12345 or 34512. Attention exchange Ai and Aj The order of is always regarded as 2 Spelling , even if
yes Ai= Aj Time .
Please calculate how many spellings satisfy the whole number K Multiple of .
【 Input format 】
The first line contains 2 Integer n and K.
The second line contains n Integer A1,A2, · · · , An.
【 Output format 】
An integer represents the answer .
【 sample input 】
4 2
1 2 3 4
【 sample output 】
6
【 Scale and agreement of evaluation cases 】
about 30% Evaluation cases for ,1 ≤ n≤ 1000, 1 ≤ K ≤ 20, 1 ≤ Ai ≤ 10^4.
For all profiling cases ,1 ≤ n≤ 10^5,1 ≤ K≤ 10^5,1 ≤ Ai ≤ 10^9.
<> test questions J: network analysis
time limit : 1.0s Memory limit : 256.0MB Total score of this question ：25 branch
【 Problem description 】
Xiao Ming is doing a network experiment .
He set n Computer , Called node , Used for sending, receiving and storing data .
Initial time , All nodes are independent , No connection exists .
Xiao Ming can connect the two nodes through a network cable , After connection, the two nodes can communicate with each other
Yes . If there is a network cable connection between the two nodes , Called adjacency .
Xiao Ming sometimes tests the network at that time , He will send a message at a node , The message will be sent
To each adjacent node , Then these nodes will forward to their adjacent nodes , Until all direct
Or indirectly adjacent nodes have received information . All sending and receiving nodes will store the information .
A message is stored only once .
The process of Xiaoming connection and test is given , Please calculate the size of information stored on each node .
【 Input format 】
The first line of input contains two integers n,m, Indicates the number of nodes and operations respectively . Node from
1 to n number .
next m that 's ok , Three integers per line , Represents an operation .
If the operation is 1 a b, Indicates that the node will be a And nodes b Connected by network cable . When a = b
Time , Indicates that a self ring is connected , No material impact on the network .
If the operation is 2 p t, Indicates at the node p The size of the last message sent is t Information .
【 Output format 】
Output one line , contain n Integer , Adjacent integers are separated by a space , Sequential representation
After the above operations, the node 1 To node n Size of information stored on .
【 sample input 】
4 8
1 1 2
2 1 10
2 3 5
1 4 1
2 2 2
1 1 2
1 2 4
2 2 1
【 sample output 】
13 13 5 3
【 Scale and agreement of evaluation cases 】
about 30% Evaluation cases for ,1 ≤ n ≤ 20,1 ≤ m ≤ 100.
about 50% Evaluation cases for ,1 ≤ n ≤ 100,1 ≤ m ≤ 1000.
about 70% Evaluation cases for ,1 ≤ n ≤ 1000,1 ≤ m ≤ 10000.
For all profiling cases ,1 ≤ n ≤ 10000,1 ≤ m ≤ 100000,1 ≤ t ≤ 100.
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