它通过{}和:来代替传统%方式

1、使用位置参数

>>> li = ['hoho',18] >>> 'my name is {} ,age {}'.format('hoho',18) 'my name is
hoho ,age 18' >>> 'my name is {1} ,age {0}'.format(10,'hoho') #索引取值 'my name is
hoho ,age 10' >>> 'my name is {1} ,age {0} {1}'.format(10,'hoho') 'my name is
hoho ,age 10 hoho' >>> 'my name is {} ,age {}'.format(*li) #*[]迭代列表 'my name is
hoho ,age 18'
2、使用关键字参数

>>> hash = {'name':'hoho','age':18} >>> 'my name is {name},age is
{age}'.format(name='hoho',age=19) 'my name is hoho,age is 19' >>> 'my name is
{name},age is {age}'.format(**hash) #**dict 'my name is hoho,age is 18'
3、填充与格式化

:[填充字符][对齐方式 <^>][宽度]
>>> '{0:*>10}'.format(10) ##右对齐 '********10' >>> '{0:*<10}'.format(10) ##左对齐
'10********' >>> '{0:*^10}'.format(10) ##居中对齐 '****10****'
4、精度与进制
>>> '{0:.2f}'.format(1/3) '0.33' >>> '{0:b}'.format(10) #二进制 '1010' >>>
'{0:o}'.format(10) #八进制 '12' >>> '{0:x}'.format(10) #16进制 'a' >>>
'{:,}'.format(12369132698) #千分位格式化 '12,369,132,698'
5、使用索引
>>> li ['hoho', 18] >>> 'name is {0[0]} age is {0[1]}'.format(li) 'name is
hoho age is 18

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